Question

1) What is the Newton's Third Law Pair to the force M2 exerts on M1? the force M2 exerts on earth the weight of M1 the force M1 exerts on M2 Ff the force from M1 on the floor the force from the floor on M1 Submit 2) Now, Fb is increased so that the blocks accelerate. The magnitudes of the two forces are now Ff = 35 N and Fb = 100 N. What is the magnitude of the blocks' acceleration? a= 12.5 m/s2 a= 0.833 m/s2 a= 11.7 m/s2 a= 6.43 m/s2 a= 3.1 m/s2 a= 4.76 m/s2 Submit Your submissions: E Submitted: Monday, December 9 at 1:34 PM Feedback: Feedback will be given once all questions have been attempted and the Grade cluster button has been pressed. 3) What is the x-component of F2on1, the force that block 2 exerts on block 1? F2on1,x= -65 N F2on1,x= 65 N F2on1,x= 29.4 N F2on1,x= -29.4 N F2on1,x= -44.3 N F2on1,x= 44.3 N

          1)
What is the Newton's Third Law Pair to the force M2 exerts on M1?
the force M2 exerts on earth
the weight of M1
the force M1 exerts on M2
Ff
the force from M1 on the floor
the force from the floor on M1
Submit
2)
Now, Fb is increased so that the blocks accelerate. The magnitudes of the two forces are now Ff = 35 N and Fb = 100 N.
What is the magnitude of the blocks' acceleration?
a= 12.5 m/s2
a= 0.833 m/s2
a= 11.7 m/s2
a= 6.43 m/s2
a= 3.1 m/s2
a= 4.76 m/s2
Submit
Your submissions:
E
Submitted:
Monday, December 9 at 1:34 PM
Feedback:
Feedback will be given once all questions have been attempted and the Grade cluster button has been pressed.
3)
What is the x-component of F2on1, the force that block 2 exerts on block 1?
F2on1,x= -65 N
F2on1,x= 65 N
F2on1,x= 29.4 N
F2on1,x= -29.4 N
F2on1,x= -44.3 N
F2on1,x= 44.3 N

Show more…

Added by Jessica V.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

12/08/2022

Step 1

Sure! Let's break down each question step by step. Show more…

Show all steps

lock

Thanks for your feedback!

1) What is the Newton's Third Law Pair to the force M2 exerts on M1? the force M2 exerts on earth the weight of M1 the force M1 exerts on M2 Ff the force from M1 on the floor the force from the floor on M1 Submit 2) Now, Fb is increased so that the blocks accelerate. The magnitudes of the two forces are now Ff = 35 N and Fb = 100 N. What is the magnitude of the blocks' acceleration? a= 12.5 m/s2 a= 0.833 m/s2 a= 11.7 m/s2 a= 6.43 m/s2 a= 3.1 m/s2 a= 4.76 m/s2 Submit Your submissions: E Submitted: Monday, December 9 at 1:34 PM Feedback: Feedback will be given once all questions have been attempted and the Grade cluster button has been pressed. 3) What is the x-component of F2on1, the force that block 2 exerts on block 1? F2on1,x= -65 N F2on1,x= 65 N F2on1,x= 29.4 N F2on1,x= -29.4 N F2on1,x= -44.3 N F2on1,x= 44.3 N

Play audio

Feedback

Powered by NumerAI

Ivan Kochetkov and 57 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 Hello, here we have to solve the following problem.

00:02 Three blocks in question 1 have the following masses.

00:08 4, 8 and 7 kilograms.

00:14 They are placed on the frictionless floor and two forces f of 25 newtons and b of 28 neutons are applied.

00:30 In question 1, and here we have to determine the force which block m3 exerts on block m2.

00:41 Let's do this, let's calculate it.

00:44 And here, first of all, let's start with each individual block.

00:47 Let's look at the block m3.

00:50 It experiences gravity, normal reaction, force fb, to the right, to the left, sorry, and force f2 on 3.

01:03 The block in the middle, m2, is experiencing gravity, normal reaction, and 2, f3 on 2, and also it experiences f1 on 2.

01:25 And the block, which is on the very left, is experiencing f, f to the left, to the right, sorry, and f2 on 1 to the left.

01:38 And of course, no normal reaction and gravity.

01:42 And overall here, fb is greater, that's why it's fairer for us.

01:46 To presume that the system is moving with acceleration to the left.

01:50 Therefore, let's write down equations, second newton's low equation for the first block, for all of the blocks, let's start with the block one, now block two, now for block three.

02:25 Now let's calculate the sum of all these three equations and therefore acceleration of the system is a difference between fb and ff over total mass...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later