1) What mass of copper (II) sulfate pentahydrate is required to prepare 500 mL of a 0.20 mol/litre solution. (Hint: the molar mass of CuSO4 * 5H2O is 249.71 g/mol) Briefly outline how you would prepare this solution in the lab.
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20 mol/L solution in 500 mL. Moles = Molarity × Volume (in L) Moles = 0.20 mol/L × 0.500 L Moles = 0.100 mol Now, we need to find the mass of copper (II) sulfate pentahydrate required. Mass = Moles × Molar Mass Mass = 0.100 mol × 249.71 g/mol Mass = 24.971 Show more…
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