To find the volume of \(0.40 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_2\) needed, we can use the equation:
\(\mathrm{M}_1 \cdot \mathrm{V}_1 = \mathrm{M}_2 \cdot \mathrm{V}_2\)
Where:
\(\mathrm{M}_1\) = initial molar concentration of the solution (0.40
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