00:01
Hello students, so the first part of the question is to calculate the new ph of the solution.
00:09
So this is the reaction equation now.
00:12
So here as we can see that this ch3ooh, hello student, so the question is to calculate the new ph of the reaction equation.
00:26
So here this is the reaction equation where this naoh is the strong base and the forming acid over here is the weak acid.
00:38
So here this will form the salt and the water.
00:44
So here it will, as nahcooh is a salt of weak acid and a strong base, so it will act as a buffer solution.
00:57
So now we will use the henderson -hasselbalch equation to calculate the ph.
01:01
So the henderson -hasselbalch equation is ph is equal to pka plus log of a - ions divided by acid concentration.
01:16
So here where the pka is the dissociation constant of the weak acid, so here the concentration of the conjugate base is nahcooh and the ha is the concentration of the weak acid.
01:32
So in this case, the concentration of ha is equal to 0 .85 moles given in the question and the a - ions is equal to 0 .75 moles...