Question

1. \( x+y \leqslant 3 \) \begin{tabular}{c|c|c} \( x \) & 0 & 3 \\ \hline\( y \) & 3 & 10 \end{tabular} \[ \begin{array}{c} x+y \leq 3 \\ 0+3 \leq 3 \\ 3 \leq 3 \end{array} \] \( 2 \cdot-x+y \leq 3 \) 3. \( x-y<2 \)

          1. \( x+y \leqslant 3 \)
\begin{tabular}{c|c|c} \( x \) & 0 & 3 \\ \hline\( y \) & 3 & 10 \end{tabular}
\[
\begin{array}{c}
x+y \leq 3 \\
0+3 \leq 3 \\
3 \leq 3
\end{array}
\]
\( 2 \cdot-x+y \leq 3 \)
3. \( x-y<2 \)

1. x+y ⩽ 3
x 0 3
y 3 10

x+y ≤ 3

0+3 ≤ 3

3 ≤ 3

2 ·-x+y ≤ 3
3. x-y<2

Added by Jason B.

Elementary Algebra

Lynn Marecek 2nd Edition

Chapter 5

Instant Answer

Solved by Expert Luke Waitrovich

08/02/2021

Step 1

The first equation is \(x + y \leq 3\). This means that the sum of x and y should be less than or equal to 3. The table gives us two pairs of x and y values: (0,3) and (3,10). For the first pair (0,3), if we substitute these values into the equation, we get 0 + 3 Show more…

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