00:02
Hello students, given circuit is positive clamper with negative reference voltage of 10 volt.
00:14
Now if positive voltage is given, it will make diode as reverse bi -acid i .e.
00:27
Open circuit and negative voltage will make forward bi -acid.
00:43
This forward bi -acid will make short circuit.
00:52
Now consider negative voltage applied condition to find steady state voltage.
00:59
Here we can observe if negative voltage given it is forward bi -acid so take plus vi plus vc and minus 10 is equal to 0 which is from nodal analysis.
01:16
From this input voltage is 20 volt plus vc minus 10 is equal to 0.
01:23
Then steady state voltage will be equal to minus 10 volt.
01:33
Next we need to consider positive voltage condition.
01:37
When positive voltage is given, it will make open circuit.
01:41
So now consider it is reverse bi -acid hence take a negative vi plus vc plus output voltage v0 is equal to 0...