00:01
Hello students, in this question given as the distance ac is equals to 3 meter, pc is equals to 6 meter, load applied load on the beam is 8 kilo newton per meter and applied force is equals to 40 kilo newton at angle theta is equals to 60 degree.
00:32
Now, we have to calculate the internal normal force.
00:36
So for this, we will apply the equilibrium condition along the x -axis.
00:41
So total force along the x -axis should be equal to the zero.
00:47
So for that, the internal normal force at point c minus f cos theta is equals to zero.
00:59
So this is equals to the 40 kilo newton into cos of 60 degree.
01:06
So after calculation, the normal internal force at point c will be equal to the 20 kilo newton.
01:16
Now, next, we have to calculate the shear force at the point c.
01:22
So for this, we have to apply the force along the y -axis should be equal to the zero.
01:29
So this will be shear at the point c minus load into 3 meter minus 1 by 2 into p into 3 minus f sin theta is equals to zero...