00:01
In this question we are given that there are four forces acting right.
00:05
Let me write them one by one.
00:09
F1 acts at an angle that makes this is what? 4, this is 3 and this is 5.
00:22
This angle would be 307 degrees or we can say that this angle is 37 degrees.
00:29
This is 8 newton.
00:31
Is it newton or kilo -neutral? kilo -neutral.
00:35
8 -klo -neuton.
00:37
This is f2 this x at this is 4 now this is so this angle would be 53 degrees so let us say this is 53 degrees now the third force is like this this has a value of 4 kilo and the fourth force is like this this has a value of 6 kiloons now let us break all of them in the vector components this 8 kilunutton will have two components, one like this and another like this.
01:20
If this is 37, this would be 37.
01:23
8 cost 37.
01:24
8 cost 37 means 8 into 4 by 5.
01:29
8 into 4 by 5.
01:30
So this is 6 .4.
01:34
And this would be 8.
01:36
Sin 37, that means 8 into 3 by 5.
01:41
So this would be 4 .8 kilo.
01:45
Similarly, this would be having two components, one upwards.
01:48
And the one you would be the right about it.
01:50
This would be f2, sine 53, that is point a times f and it would point 6 times f.
01:57
So if you write the net forces, it will be some of all of these components.
02:03
So in the i cap direction, what are the portraits? this is minus 4, this is minus 6, this is plus 6 .4, this is plus 0 .4, this is plus 0 .6...