(10 points) Given the information in the table below, construct a d-orbital energy diagram with electrons included for the square planar complex [Pt(NH$_3$)$_4$]$^{2+}$ and give the crystal field stabilization energy (CFSE) and the number of unpaired electrons in this complex. Assume low-spin type behavior.
Ligand Subset
$d_{xy}$
$d_{xz}$
$d_{yz}$
$d_{x^2-y^2}$
$d_{z^2}$
One ligand on z-axis
-0.314 Δ$_o$
+0.057 Δ$_o$
+0.057 Δ$_o$
-0.314 Δ$_o$
+0.514 Δ$_o$
Two ligands at 90°
+0.114
-0.257
-0.257
+0.614
-0.214
angle on xy-plane
Three ligands at 120°
+0.546
-0.386
-0.386
+0.546
-0.321
angles on xy-plane
Four ligands in
tetrahedral
+0.178
+0.178
+0.178
-0.267
-0.267
arrangement
Energy
0 Δ$_o$
CFSE =
Number of unpaired electrons =