00:02
Hello students, in the given circuit we need to find equivalent circuit for this.
00:07
First here r1 and r2 are in series.
00:11
So, combining these two r1 plus r2 we get 100 plus 100 200 ohm.
00:19
Then again r3 r4 r5 are in series.
00:24
So, combine these three we get 1 plus 2 plus 3 that is 6 kilo ohm.
00:35
Then 6 and 7 are in series.
00:40
Again combine this to 500 plus 100 we get 600 ohm.
00:47
Now r3 r4 r5 r6 r7 and r8 are in parallel to each other.
00:56
Now we can combine from r3 to r8 that is from 3 to 8 these are in parallel to each other.
01:08
In order to obtain the value for this we can use parallel formula that is 1 divided by r3 to 8 is equal to 1 divided by r3 4 5 plus 1 divided by r67 plus 1 divided by r8.
01:32
Now substituting the values here that is 1 divided by 6000 plus that is 6 kilo ohm 1 divided by 600 plus 1 divided by r8 value that is 2700 because 2 .7 kilo ohm.
02:02
From this calculation we get 1 by r3 to 8 reciprocating this we obtain the value of resistance 3 to 8.
02:16
Finally r9 and r10 are parallel to each other.
02:23
The calculation for this will be 1 by r9 plus 1 by r10 which is we obtained 0 .5 kilo ohm.
02:41
From this now r1 to 10 can be calculated by adding 200 plus 6000 plus 453 .78 plus 0 .5 kilo can be written as 500.
03:03
From all this calculation we obtained equivalent resistance will be 7153 .78 ohm...