00:01
Hi.
00:02
So we have first question here.
00:05
And a known gas effuses at a rate of 0 .5 times the rate of h4.
00:10
What is the molar mass of the gas? so remember that graham's law of fusion states that the rate of gas a would be inversely proportional to the molar mass of gas a.
00:26
And that means if we write that, if we compare that with another gas, then we'll have this equation.
00:31
Molar mass of b over the molar mass of a.
00:39
So let's say that a here would be the unknown gas and b is ch4.
00:51
So that means the rate of the unknown gas over the rate of ch4, equivalent to the molar mass of ch4 over the molar mass of a.
01:04
And our unknown is the molar mass of the unknown gas.
01:07
So we'll just rearrange this.
01:09
Molar mass of the unknown gas would be equivalent to the molar mass of ch4 over rate of a over rate of ch4.
01:23
So plug in the values here.
01:25
The molar mass of ch4 is 12 .01 plus the atomic mass of hydrogen, 1 .01 times 4.
01:36
That's 16 .05 grams per mole.
01:41
So 16 .05 grams per mole.
01:45
What's the rate of a? rate of a is 0 .5 times the rate of ch4.
01:57
So 0 .5 multiplied by the rate of ch4.
02:01
And in the denominator, we have the rate of ch4.
02:03
It's not specified.
02:05
So i'm just writing rate of ch4...