00:01
Hi, hello, here they are asking that to calculate delta h and delta u, two different conditions they given.
00:07
So actually here the formula is delta u equal to, so q plus w.
00:13
So this is the first law of thermodynamics.
00:16
So according to these, the temperature they given is, so t final minus t initial means t2 minus t1.
00:25
So according to the temperatures they given.
00:27
So 348 minus 298 kelvin so then it will becomes that 50 kelvin so delta e is become 50 kelvin's so they are asking that to calculate delta h and delta u so but according to the cp for the dynamic molecule and cp value is so 29 .0 .0 .9 jowl per mole and and cv value is, so 21 jowl per mole kelvin's.
01:05
So here, so delta u becomes what, n, cv, delta t.
01:10
So for delta u, if we will substitute these values, so 0 .446 moles multiplies with, so 21 jowl per moles and 50 kelvin's.
01:25
So then this will becomes that 463 .5 zoll.
01:32
So as it is 463 .5 zolls, so the delta u value...