100 mol/h of benzene (C6H6) and 200 mol/h of chlorine (Cl2) are fed to a reactor. The exit stream was analysed and found to contain 10.0 mol/h of Cl2, 20.0 mol/h of C6H5Cl, and 40.0 mol/h of C6H4Cl2. 1. Sketch the problem (2) 2. Solve the problem (mean find all the unknowns) using the extent of reaction method, and molecular species approach. Show all steps. (10) 3. Calculate the percent conversion of benzene. (2) 4. Find the yield and selectivity of the process. (2) 5. What can be done to improve the selectivity? Explain in your words? (2) 6. How to improve the overall conversion. While answering this question, keep in mind the economics of the process, initial cost for any change in the process and final cost of the product. Discuss all the advantage and disadvantage of your proposed solution. (7). The chlorination of benzene occurs via the following reactions: C6H6 + Cl2 \rightarrow C6H5Cl + HCl C6H5Cl + Cl2 \rightarrow C6H4Cl2 + HCl C6H4Cl2 + Cl2 \rightarrow C6H3Cl3 + HCl
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Given: - Benzene (C6H6) fed = 100 mol/h - Chlorine (Cl2) fed = 200 mol/h - Chlorine (Cl2) in the exit stream = 10.0 mol/h To find the moles of benzene (C6H6) that reacted, we need to subtract the moles of chlorine (Cl2) in the exit stream from the moles of Show more…
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