00:01
Hello everyone.
00:02
So today i will be solving this question for you.
00:04
Let me write the solution over here.
00:06
So basically in this question we have been given that the full scale deflection current that is represented by ig for a galvanometer is equal to 1 ,000 millie ampere.
00:15
Or we can write that it is equal to 1 ,000 into 10 to the power minus 3 ampere.
00:21
So 1 milamper because it is equal to 10 to the power minus 3 ampere.
00:26
And we have been given that the resistance for the galvanometer, it is equal to, 3 oom and the potential difference, the voltometer, it measures a potential difference, a range of 10 volt.
00:38
Okay.
00:39
Now from here, we can find the resistance because we have to find the resistance.
00:44
Okay.
00:45
Connected to the galvanometer.
00:46
So we can do that by using the formula that r would be equal to, let's say this is r.
00:50
So r would be equal to and this is v...