00:01
Hi, here in this given problem, first of all, we draw a cartesian plane.
00:07
Cartesian plane having x -axis, y -axis.
00:12
One of the charge has been kept, the charge q1 at a point a and this is a positive charge, a positive charge this is, q1 at point a.
00:34
Another positive charge put at origin, suppose the origin is represented as b and this is charge q2 and the third charge, this is negative charge q3.
00:50
Suppose it is put at the point c.
00:53
Now the distances and the values of the charges starting with this ab that is given as r1 and this is 3 .00 centimeter.
01:06
Centimeter.
01:08
Observation point is marked over here.
01:11
Suppose this is p.
01:13
So now bc that is given as r3 and this is 2 .00 centimeter and the distance of observation point this r that is bp this is 1 .00 centimeters.
01:34
So distance of this observation point from a it will become it will remain because ab is 3 centimeter so it will remain 2 centimeter and from c this distance will become 2 plus 1 means 3 .00 centimeter...