10. A ballerina spins initially at 1.5 rev/s when her arms are extended. She then draws in her a

Name: 10. A ballerina spins initially at 1.5 rev/s when her arms are extended. She then draws in her arms to her body and her moment of inertia becomes 0.88 kg · m^2, and her angular speed increases to 4.0 rev/s. What was her initial moment of inertia? [10 points]
Uploaded: 2023-09-04T14:43:02-08:00
Duration: 1 min 41 s
Channel: Supreeta N
Description: 10. A ballerina spins initially at 1.5 rev/s when her arms are extended. She then draws in her arms to her body and her moment of inertia becomes 0.88 kg · m^2, and her angular speed increases to 4.0 rev/s. What was her initial moment of inertia? [10 points]

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Ankur S · Accepted Answer

1. We know that angular momentum is conserved when there is no external torque acting on the sys

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10. A ballerina spins initially at 1.5 rev/s when her arms are extended. She then draws in her arms to her body and her moment of inertia becomes 0.88 kg · m^2, and her angular speed increases to 4.0 rev/s. What was her initial moment of inertia? [10 points]

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