Question

10.6. Eleven employees were put under the care of the company nurse because of high cholesterol readings. The nurse lectured them on the dangers of this condition and put them on a new diet. Shown are the cholesterol readings of the 11 employees both before the new diet and one month after use of the diet began. Using the critical value method, at 95% level of confidence, using the data below test to see if the cholesterol readings of the employees have changed. Assume the differences in cholesterol readings are normally distributed in the population. EMPLOYEE BEFORE AFTER 1 255 197 2 230 225 3 290 215 4 242 215 5 300 240 6 250 235 7 215 190 8 230 240 9 225 200 10 219 203 11 236 223

          10.6. Eleven employees were put under the care of the company nurse because of high cholesterol readings. The nurse lectured them on the dangers of this condition and put them on a new diet. Shown are the cholesterol readings of the 11 employees both before the new diet and one month after use of the diet began. Using the critical value method, at 95% level of confidence, using the data below test to see if the cholesterol readings of the employees have changed. Assume the differences in cholesterol readings are normally distributed in the population.
EMPLOYEE BEFORE AFTER
1 255 197
2 230 225
3 290 215
4 242 215
5 300 240
6 250 235
7 215 190
8 230 240
9 225 200
10 219 203
11 236 223

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10.6. Eleven employees were put under the care of the company nurse because of high cholesterol readings. The nurse lectured them on the dangers of this condition and put them on a new diet. Shown are the cholesterol readings of the 11 employees both before the new diet and one month after use of the diet began. Using the critical value method, at 95% level of confidence, using the data below test to see if the cholesterol readings of the employees have changed. Assume the differences in cholesterol readings are normally distributed in the population.
EMPLOYEE BEFORE AFTER
1 255 197
2 230 225
3 290 215
4 242 215
5 300 240
6 250 235
7 215 190
8 230 240
9 225 200
10 219 203
11 236 223

Added by Donald M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert David Nguyen

08/05/2022

Step 1

The null hypothesis states that there is no change in the cholesterol readings of the employees after the diet. The alternative hypothesis states that there is a change in the cholesterol readings of the employees after the diet. Null hypothesis (H0): μd = Show more…

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10.6. Eleven employees were put under the care of the company nurse because of high cholesterol readings. The nurse lectured them on the dangers of this condition and put them on a new diet. Shown are the cholesterol readings of the 11 employees both before the new diet and one month after use of the diet began. Using the critical value method, at 95% level of confidence, using the data below test to see if the cholesterol readings of the employees have changed. Assume the differences in cholesterol readings are normally distributed in the population. EMPLOYEE BEFORE AFTER 1 255 197 2 230 225 3 290 215 4 242 215 5 300 240 6 250 235 7 215 190 8 230 240 9 225 200 10 219 203 11 236 223

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Transcript

00:01 Hi, i'm david and i'm here to have you and see your question.

00:03 Now let me bring up your question here.

00:06 In the question here, we are going to discuss about the hypothesis testing.

00:10 He wants to test if the criterion readings of the employees has changed.

00:15 And it means that we need to find the known hypothesis with the mud equal to the 0 versus the alternative hypothesis and the mud will not equal to the zero.

00:26 Notice that this will be the two -tale test.

00:30 Now to test this one in your question we're given the table on the data for the before and after.

00:36 So let me copy the table and then i put it on the right here and i will make it small.

00:48 We'll put it maybe on the left.

00:51 And from here, first of all i need to find the difference d.

00:55 I will turn the before, i will minus the after.

00:59 So we have to 55 we minus the 197 equal to 5.

01:04 To the 58, 230 minus 225, equal to the 5, and then 290 minus the 215, equal to the 75, 242 minus the 215, 27, 300 minus 240 will be the 60, and this one will be the 15, and this will be the 15, and this will be the 25, this will be equal to the minus 10.

01:35 And this will be the 25 and 219 minus 203 equal to the 16 to 36 minus 223 equal to the 13.

01:50 Now with the new dataset here we need to find the n will equal to totally will be the 11 of them and we need to find the d bar the mean...

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