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10.A block of copper of unknown mass has an initial temperature of 65.4 °C. The copper is immersed in a beaker containing 95.7 g of water at 22.7 °C. When the two substances reach thermal equilibrium, the final temperature is 24.2 °C. What is the mass of the copper block? Cs (copper) = 0.385 J/g•°C 

          10.A block of copper of unknown mass has an initial temperature of 65.4 °C. The copper is immersed in a beaker containing 95.7 g of water at 22.7 °C. When the two substances reach thermal equilibrium, the final temperature is 24.2 °C. What is the mass of the copper block? Cs (copper) = 0.385 J/g•°C
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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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10.A block of copper of unknown mass has an initial temperature of 65.4 °C. The copper is immersed in a beaker containing 95.7 g of water at 22.7 °C. When the two substances reach thermal equilibrium, the final temperature is 24.2 °C. What is the mass of the copper block? Cs (copper) = 0.385 J/g•°C
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A block of copper of unknown mass has an initial temperature of 65.4 ºC. The copper is immersed in a beaker containing 95.7 g of water at 22.7 ºC. When the two substances reach thermal equilibrium, the final temperature is 24.2 ºC. What is the mass of the copper block? Cs H2O = 4.184 J/g º C Note: You must show your work to receive credit – Include formulas, unit conversions and cancellations

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Transcript

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00:01 Hello students in this problem we have given a block of copper of unknown mass m is at initial temperature of 65 .4 degrees celsius and it is immersed in water having 95 .7 gram mass at initial temperature 22 .7 degrees celsius.
00:27 The two substances reaches a final temperature of 24 .7 degrees celsius.
00:29 The two substances reaches a final temperature of 24.
00:32 2 degrees celsius mass of copper we have to determine the specific heat of copper is 0 .385 jule per gram degrees celsius so we can here write that from the principle of calerometry heat released will be equals to heat gained so released will be by copper and gain heat will be by water so we can write m c and this is final temperature t minus release is so t initial minus t and that will be m w c w and this is t minus t initial for the w okay so now we have the values so mass m 0 .385 jule per gram degree celsius okay this is 65 .4 degrees celsius minus 24 .2 .2 degrees celsius...
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