Question

10) Solve the word problem. $A = lw$ $A = bh$ $V = Bh$ The bottom of Aldriana's rectangular jewelry box has an area of $40\frac{1}{2}$ square inches. If the height of the box is $3\frac{1}{3}$ inches, what is the area of its base and its volume? Volume _____ $V = 135$ in$^3$ $V = 123\frac{8}{9}$ in$^3$ $V = 146\frac{1}{9}$ in$^3$

          10) Solve the word problem.
$A = lw$
$A = bh$
$V = Bh$
The bottom of Aldriana's rectangular jewelry box has an area of $40\frac{1}{2}$ square inches. If the height of the box is $3\frac{1}{3}$ inches, what is the area of its base and its volume?
Volume _____
$V = 135$ in$^3$
$V = 123\frac{8}{9}$ in$^3$
$V = 146\frac{1}{9}$ in$^3$

10) Solve the word problem.
A = lw
A = bh
V = Bh
The bottom of Aldriana's rectangular jewelry box has an area of 40(1)/(2) square inches. If the height of the box is 3(1)/(3) inches, what is the area of its base and its volume?
Volume
V = 135 in^3
V = 123(8)/(9) in^3
V = 146(1)/(9) in^3

Added by Teresa C.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

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Solve the word problem. A = lw A = bh V = Bh 1. The bottom of Aidriana's rectangular jewelry box has an area of 40 square inches. If the height of the box is 3 inches, what is the area of its base and its volume? Volume V = 135 in^3 V = 123 in^3 6 in^3 9 in^3