00:01
Hi, this is a question based on thermodynamics, so thermodynamics, so where we have n is equal to so number of molecules is equal to 2 moles and p1 is equal to 1 atm that is 101 .325 kilo pascal.
00:21
So, we are given with the value of temperature t1 as 20 degree celsius which is equal to 293 kelvin and we have the value of specific heat ratio is equal to 1 .67 and we are given with the final volume is 3 times the initial volume.
00:39
Now we have the value of so we know that ideal gas equation is given by pv is equal to nrt, so we have first is the isobaric process, so isobaric expansion, so isobaric expansion we have the graph of, so we have the graph of p versus v, so pv curve where p is constant, so the pressure will be constant, so p1 is equal to p2 but the volume changes, so volume this is v1 and this volume is v2, so that so this is v1 minus v2.
01:16
Now we have work done is equal to p into v, so this is p1 into, so p1 is equal to p2, it is v2 minus v1, so we know that v2 is 3 times the v1, so work done is equal to, so this is for first case that is a isobaric expansion, so work done is equal to p into 3v1, so this is p is equal to, so this is 3v1 minus v1 which is equal to 2p1v1, so p1v1 is nothing but it is n into rt, so 2 into n rt1, so this is 2 into, n is 2 moles into 8 .314 into temperature is 293 kelvin, therefore the work done for isobaric expansion that is the first case, so for this case it is 9739 .32 joules...