Question

11. A fluoride ion-selective electrode has a selectivity coefficient K_F-,OH-^Pot = 0.1. What will be the change in electrode potential when the pH of the solution increases from 5 to 12? The concentration of the F- ions in the solution is 1.0 × 10^-4 M. The potential of an ion selective electrode can be calculated using formula E = constant ± (0.05916 / zA) log(AA + ?I KA,I AI). a. ?E = -0.62 mV b. ?E = -6.2 mV c. ?E = -62.0 mV d. ?E = -622.0 mV

          11. A fluoride ion-selective electrode has a selectivity coefficient K_F-,OH-^Pot = 0.1. What will be the change in electrode potential when the pH of the solution increases from 5 to 12? The concentration of the F- ions in the solution is 1.0 × 10^-4 M. The potential of an ion selective electrode can be calculated using formula E = constant ± (0.05916 / zA) log(AA + ?I KA,I AI).
a. ?E = -0.62 mV
b. ?E = -6.2 mV
c. ?E = -62.0 mV
d. ?E = -622.0 mV

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11. A fluoride ion-selective electrode has a selectivity coefficient KF-,OH-^Pot = 0.1. What will be the change in electrode potential when the pH of the solution increases from 5 to 12? The concentration of the F- ions in the solution is 1.0 × 10^-4 M. The potential of an ion selective electrode can be calculated using formula E = constant ± (0.05916 / zA) log(AA + ?I KA,I AI).
a. ?E = -0.62 mV
b. ?E = -6.2 mV
c. ?E = -62.0 mV
d. ?E = -622.0 mV

Added by Christopher S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Suman K

05/10/2022

Step 1

This is because pH is the negative logarithm of the hydrogen ion concentration, and an increase in pH means a decrease in hydrogen ions and an increase in hydroxide ions (OH-). The selectivity coefficient KPOH of 0.1 means that the electrode is 10 times more Show more…

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A fluoride ion-selective electrode has a selectivity coefficient K_F-,OH-^Pot = 0.1. What will be the change in electrode potential when the pH of the solution increases from 5 to 12? The concentration of the F- ions in the solution is 1.0 x 10^-4 M. The potential of an ion selective electrode can be calculated using formula E = constant ± (0.05916 / zA) log(AA + ΣI KA,I AI). a. ΔE = -0.62 mV b. ΔE = -6.2 mV c. ΔE = -62.0 mV d. ΔE = -622.0 mV

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