00:01
In this question, we have been given that an electron is moving in the positive x -axis direction.
00:09
So, let us consider that the direction of velocity is along the positive x -axis and the deflection of the electron is along the negative of y -axis.
00:21
That means force will be acting along this direction.
00:25
So, for sign convenience, we can consider the axis as the horizontal is x, this one is y and in this direction we will have z direction.
00:38
Now, here we can write velocity of electron v equal to v i cap that means along the horizontal direction and force f is equal to minus f j cap.
00:59
Now, here charge is electron so we can write this q equal to minus of e where e is equal to 1 .6 times 10 raised to the power minus 19 coulomb.
01:13
Now, here we need to find the direction of magnetic field.
01:17
So, here as we know that force f is equal to q times the cross product between velocity and the magnetic field.
01:30
So, if we consider that magnetic field is acting along n cap of b...