Question

Consider the quadratic model h(t) = -16t^2 + 40t + 50 for the height (in feet), h, of an object t seconds after the object has been projected straight up into the air. Find the maximum height attained by the object. How much time does it take to fall back to the ground? Assume that it takes the same time for going up and coming down.

Name: Consider the quadratic model h(t) = -16t^2 + 40t + 50 for the height (in feet), h, of an object t seconds after the object has been projected straight up into the air. Find the maximum height attained by the object. How much time does it take to fall back to the ground? Assume that it takes the same time for going up and coming down.
Uploaded: 2022-07-11T18:08:27-08:00
Duration: 2 min 24 s
Channel: Gregory Higby
Description: Consider the quadratic model h(t) = -16t^2 + 40t + 50 for the height (in feet), h, of an object t seconds after the object has been projected straight up into the air. Find the maximum height attained by the object. How much time does it take to fall back to the ground? Assume that it takes the same time for going up and coming down.

          Consider the quadratic model h(t) = -16t^2 + 40t + 50 for the height (in feet), h, of an object t seconds after the object has been projected straight up into the air. Find the maximum height attained by the object. How much time does it take to fall back to the ground? Assume that it takes the same time for going up and coming down.

Consider the quadratic model h(t) = -16t^2 + 40t + 50 for the height (in feet), h, of an object t seconds after the object has been projected straight up into the air. Find the maximum height attained by the object. How much time does it take to fall back to the ground? Assume that it takes the same time for going up and coming down.

Added by Melissa M.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Gregory Higby

07/11/2022

Step 1

This can be done by using the formula for the time to reach the maximum point of a quadratic function: \(t = \frac{-b}{2a}\), where \(a = -16\) and \(b = 40\). Plugging in the values, we get \(t = \frac{-40}{2*(-16)} = 1.25\) seconds. Show more…

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