11. Find the domain of the function \[ f(x)=\frac{x+1}{x^{2}-2 x-48} \] A. \( (-\infty,-6) \cup(-6,-1) \cup(-1,8) \cup(8, \infty) \) B. \( (-\infty,-6) \cup(-6,8) \cup(8, \infty) \) C. \( (-\infty,-1) \cup(-1, \infty) \) D. \( (-\infty, \infty) \) E. \( (48, \infty) \) F. None of the above
Added by FΓ‘tima I.
Close
Step 1
The denominator is a quadratic equation, \(x^{2}-2x-48=0\). We can solve this equation by factoring: \(x^{2}-2x-48=(x-8)(x+6)=0\) Setting each factor equal to zero gives the solutions x=8 and x=-6. Show moreβ¦
Show all steps
Your feedback will help us improve your experience
Sherrie Fenner and 79 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Domain of the function $f(x)=\sqrt{\frac{2 x}{1+x}}$ is (a) $(-\infty, \infty)$ (b) $(-\infty,-1) \cup[0, \infty)$ (c) $(-1,1)$ (d) $(-1, \infty)$
The domain of the definition of the function $f(x)=\frac{1}{4-x^{2}}+\log _{10}\left(x^{3}-x\right)$ is: (a) $(-1,0) \cup(1,2) \cup(3, \infty)$ (b) $(-2,-1) \cup(-1,0) \cup(2, \infty)$ (c) $(-1,0) \cup(1,2) \cup(2, \infty)$ (d) $(1,2) \cup(2, \infty)$
Domain of definition of the function $f(x)=\left[3 /\left(4-x^{2}\right)\right]+\log _{10}\left(x^{3}-x\right)$ is (a) $(-1,0) \cup(1,2) \cup(2, \infty)$ (b) $(-1,0) \cup(1,0)$ (c) $(-2,2)$ (d) $(1,2) \cup(2, \infty)$
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Watch the video solution with this free unlock.
EMAIL
PASSWORD