00:01
Hello, so the first step is to know our coordinates.
00:03
So let's assign coordinate positions based on the diagram.
00:06
So this is just a tiny graph here.
00:19
We're going to have our point and our coordinate.
00:25
And this is going to be, we have a through g, a, b, c, d, e, f, g, and their coordinates, 2, 2, 0, 2, 0, 2, 0, 0, 0, 0, 0, 0 .0, 0 .0.
00:58
0 .2, 3, 4 .2, 2, 2, 2.
01:05
And then, or excuse me, this is 4 .2 .0.
01:10
This is 4 .2, comma, 2, 2 .2.
01:12
And then we have 2 .0.
01:15
This is the same as a, the load applied vertically downwards.
01:18
So the directions.
01:20
Next, we have to find the direction vectors and univctors.
01:23
So let's find univctors for the tension forces.
01:25
So the first one is going to be b, d.
01:28
So the rbd is going to equal d minus b, which is equal to 0 to 3 minus 0 to 0 .00, that's going to give us a value of 0 .0 .3.
01:45
The unit vector is going to be 0 .0 .3 over 3.
01:51
That's going to give us 0 .0 .1 .1 .1 .1.
01:54
Now, for e .f, we have r .ef is equal to.
02:03
4 .2, 2, minus 4 .2 .0 .0 .0 .0 .2.
02:08
We're left with 0 .0 .2.
02:11
And then again, to find our univector, we have uef is equal to 0 .0 .2 all over 2, and that's going to give us 0 .0 .1.
02:22
And now the univector for cd, well, right over here, is given to be 0, so we skip it.
02:30
So that's going to be equal to 0.
02:32
Now lastly, we have the forces acting upon one another...