00:01
Okay, so we're asking the products for the following reactions.
00:03
And in the first one, we are reacting sodium -mothoxide.
00:08
I'm sorry, diethyl -heptane diet with sodium -mothoxide and hcl.
00:18
2, 3, 4, 5, 6.
00:24
1, 2, 3, 4, 5, 6.
00:34
Okay, so sodium methoxide and hcl.
00:40
So sodium methoxide is going to depurtenate the alpha hydrogen, and this is going to attack the carbonyl -carbon.
00:46
So it's an intramolecular aldol reaction.
00:51
So this is going to be carbon one.
00:55
I'm sorry, hold on.
00:57
It's going to depotinate the carbon leading to the most stable ring, which is a six carbon ring.
01:04
So if we depertinate this hydrogen, we'll have a 1, 2, 3, 4, 5, 6, 7.
01:10
If we de pertinate this one, we're going to have a 5 carbon ring, and 5 carbon rank is more stable than 6.
01:17
So it's going to deprotinate this carbon.
01:19
So we've got a carbanae eye right there.
01:21
This is going to attack the carbonyl carbon.
01:23
So 1, 2.
01:27
5 carbon ring.
01:29
And carbon 1 is attached to the co ester here.
01:41
And this is carbon 1.
01:45
Carbon 5, which is the carbonyl, is now an oxide ion.
01:50
And it's also bound to an ester as well.
01:53
So this bond is going to reform.
01:55
It's going to expel the ester.
01:58
And we're going to get this.
02:01
Structure.
02:07
So for b, we have petinic acid with pbr3 and br2.
02:28
This is over water.
02:37
So pbr3 is going to replace the o .h with birmingham and another burmium is going to add to the alpha carbon of the carbony.
02:46
So this is the hell, full, hard, solansky reaction.
02:52
So get that product.
02:55
And for c, we have acetone with ethylacetate.
03:10
So acetone and ethylacetate.
03:24
So with sodium with oxide.
03:28
And the second step is to react it with hcl.
03:33
So again, it's going to deprardineate the alpha hydrogen.
03:37
And we can get two products.
03:38
So structure one, can attack structure two, or two can attack one.
03:43
So if one attacks two, deprotonate this hydrogen.
03:48
So it's going to attack the carbonyl carbon, and it's going to reform.
03:51
To expel the ester.
03:57
So carbon two is the carbon ion.
03:59
Carbon three is the ketune and it's found to this methyl as well.
04:05
So we get the structure.
04:14
So for d, we have diethyl two hexyl, two ethyl hexane diuret.
04:29
So one, two, three, four, five, six.
04:35
And on carbon two, even ethyl.
04:41
So this is going to peridate the alpha hydrogen, when reacting with sodium dioxide and hcl so we're going to pertinate this carbon and it's going to attack the carbon on carbon so one two three four five five carbon ring and on so carbon one is attached to again this this group and carbon five this is one five carbon two is the ethyl carbon five is going to be a ketone once it kicks out the ester.
05:40
So get that structure.
05:44
So for e.
05:46
We're reacting diethylmalinate with sodium dioxide, isobel bromide, and hcl.
05:53
So diethylumal malinate is actually the melanic ester.
05:57
It's another name for it.
05:59
So regardless, we'll be left for the two carbon carbox acid.
06:04
And we're reacting the structure with, again, sodium dioxide, and then an alcohol halide.
06:18
So this is going to deprediant the alpha hydrogen.
06:22
This is going to attack.
06:25
This is going to attack the aquilide...
