11 The solution set of the equation $x - 1 = \sqrt{2x + 6}$ is (1) $\{5, -1\}$ (2) $\{5\}$ (3) $\{-1\}$ (4) $\emptyset$
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Step 1: Square both sides of the equation to get rid of the square root: $(x - 1)^2 = (\sqrt{2x + 6})^2$ $x^2 - 2x + 1 = 2x + 6$ Show more…
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