Given:
- Pressure in inches of mercury = 3.0 inches
- Density of mercury = \(8486 \, \text{lbm/ft}^3\)
- Density of water = \(624 \, \text{lb/ft}^3\)
First, convert inches of mercury to feet of mercury:
\[ 3.0 \, \text{inches} = \frac{3.0}{12} \,
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