Step 2:
The sum of these three consecutive odd integers is $(x-2) + x + (x+2) = 3x$.
Step 3:
We are given that $d$ is one of the three integers. So, $d$ can be $x-2$, $x$, or $x+2$.
Case 1: $d = x-2$
If $d = x-2$, then $x = d+2$.
The sum is $3x = 3(d+2) =
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