Question

11.3 ??? ?? ?? ?? ??? DTFT? ???. (a) $x[n] = \begin{cases} 1, & 0 \le n \le 2 \\ 0, & 3 \le n \le 7 \end{cases}$, $N=8$ (b) $x[n] = \begin{cases} 1, & n = ?? \\ 0, & n = ?? \end{cases}$ (c) $x[n] = \cos(\frac{\pi}{2}n - \frac{\pi}{4})$

          11.3 ??? ?? ?? ?? ??? DTFT? ???.
(a) $x[n] = \begin{cases} 1, & 0 \le n \le 2 \\ 0, & 3 \le n \le 7 \end{cases}$, $N=8$
(b) $x[n] = \begin{cases} 1, & n = ?? \\ 0, & n = ?? \end{cases}$
(c) $x[n] = \cos(\frac{\pi}{2}n - \frac{\pi}{4})$

11.3 ??? ?? ?? ?? ??? DTFT? ???.
(a) x[n] = 1, 0 ≤ n ≤ 2
0, 3 ≤ n ≤ 7, N=8
(b) x[n] = 1, n = ??
0, n = ??
(c) x[n] = cos((π)/(2)n - (π)/(4))

Added by Jessica F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

12/08/2022

Step 1

Step 1: To find the DTFT of a discrete periodic signal, we can use the formula: X(e^jω) = Σ x[n] * e^(-jωn) Show more…

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11.3 마음과 같은 이산 주기 신호의 DTFT를 구하라. (1,0 ≤n <2 (a) x n] = - 0,3≤n ≤7 ㅠ (품 (c) x [n] = cos T , N=8 (b) x [n] = = 1, n = 짝수 0, n = 홀수 Find the DTFT of the following discrete periodic signals. (a) x[n] = {1, 0 =< n =< 2 {3, 3 =< n =< 7 , N= 8 (b) x[n] = 1, n=even 0, n=odd (c) x[n] = cos(0.5ㅠn-0.25n) 11.3 4 oK37lxl DTFT7 1,0n<2 (a) x[n]= , N=8 l0, 3 n<7 1,n= (b) x[n]= l0,n= TT TT