Question

Problem #1 11.57. An NMOS source follower must drive a load resistance of 100 with a voltage gain of 0.8. If $I_D = 1$ mA, $\mu_n C_{ox} = 100 \frac{\mu A}{V^2}$, $C_{ox} = 12 \frac{fF}{\mu m^2}$, and $L = 0.18 \mu m$, what is the minimum input capacitance that can be achieved? Assume $\lambda = 0$, $C_{GD} \approx 0$, $C_{SB} \approx 0$, and $C_{GS} = (2/3)WLC_{ox}$.

          Problem #1
11.57. An NMOS source follower must drive a load
resistance of 100 with a voltage gain of 0.8. If $I_D = 1$ mA,
$\mu_n C_{ox} = 100 \frac{\mu A}{V^2}$, $C_{ox} = 12 \frac{fF}{\mu m^2}$, and $L = 0.18 \mu m$, what
is the minimum input capacitance that can be achieved?
Assume $\lambda = 0$, $C_{GD} \approx 0$, $C_{SB} \approx 0$, and $C_{GS} = (2/3)WLC_{ox}$.

Problem #1
11.57. An NMOS source follower must drive a load
resistance of 100 with a voltage gain of 0.8. If ID = 1 mA,
Cox = 100 (μ A)/(V^2), Cox = 12 (fF)/(μ m^2), and L = 0.18 μ m, what
is the minimum input capacitance that can be achieved?
Assume λ = 0, CGD≈ 0, CSB≈ 0, and CGS = (2/3)WLCox.

Added by Stacy S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Chai Santi

10/23/2021

Step 1

Given that CGS = (2/3)WLCox, we can calculate CGS using the given values: CGS = (2/3)(0.18 μm)(1 μm)(100 μA/(V^2)) CGS = (2/3)(0.18)(100) CGS = 0.12 pF Show more…

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11.57. An NMOS source follower must drive a load resistance of 100 with a voltage gain of 0.8. If Ip = 1 mA, Cox = 100 μA/(V^2), Cox = 12 fF/(μm^2), and L = 0.18 μm, what is the minimum input capacitance that can be achieved? Assume λ = 0, CGD ≈ 0, CSB ≈ 0, and CGS = (2/3)WLCox.