11.86 Nickel has a face-centered unit cell with all atoms at lattice points and an edge length of 352.4 pm. The density of metallic nickel is 8.91 g/cm³. What is the mass of a nickel atom? From the atomic mass, calculate Avogadro's number.
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4 pm = 3.524 x 10^-8 cm Volume of a cube = a^3 Volume = (3.524 x 10^-8 cm)^3 Volume = 4.003 x 10^-23 cm^3 Show more…
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