Question

12. As a solid disk, with moment of inertia I = (1/2) MR², rolls over the top of a hill on a track, its speed is 80 cm/s. Assume friction losses are negligible. (a) How fast is the disk moving when it is 18 cm below the top? (b) If the track over the hill is oriented such that the disk rolls from due east to due west, in which direction is the angular momentum of the disk pointed? (BONUS) If the disk were a solid sphere, with moment of inertia I = (2/5) MR², find the percentage of kinetic energy that is gained in each component: rotational and translational.

          12. As a solid disk, with moment of inertia I = (1/2) MR², rolls over the top of a hill on a track, its speed is 80 cm/s. Assume friction losses are negligible.
(a) How fast is the disk moving when it is 18 cm below the top?
(b) If the track over the hill is oriented such that the disk rolls from due east to due west, in which direction is the angular momentum of the disk pointed?
(BONUS) If the disk were a solid sphere, with moment of inertia I = (2/5) MR², find the percentage of kinetic energy that is gained in each component: rotational and translational.

12. As a solid disk, with moment of inertia I = (1/2) MR², rolls over the top of a hill on a track, its speed is 80 cm/s. Assume friction losses are negligible.
(a) How fast is the disk moving when it is 18 cm below the top?
(b) If the track over the hill is oriented such that the disk rolls from due east to due west, in which direction is the angular momentum of the disk pointed?
(BONUS) If the disk were a solid sphere, with moment of inertia I = (2/5) MR², find the percentage of kinetic energy that is gained in each component: rotational and translational.

Added by Douglas R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Neelesh Sharma

05/11/2022

Step 1

Step 1: Calculate the velocity of the disk when it is 8 cm below the top of the hill using the energy conservation equation: Given: Initial kinetic energy (rotational) = (1/2) Iω₀² Initial kinetic energy (translational) = (1/2) mV₀² Initial potential energy = Show more…

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12. As a solid disk, with moment of inertia I = (1/2) MR², rolls over the top of a hill on a track, its speed is 80 cm/s. Assume friction losses are negligible (a) How fast is the disk moving when it is 18 cm below the top? (b) If the track over the hill oriented such that the disk rolls from due east to due west, in which direction is the angular momentum of the disk pointed? (BONUS) If the disk were solid sphere, with moment of inertia I = (2/5) MR², find the percentage of kinetic energy that is gained in each component: rotational and translational.