00:01
So this question is about the reaction between ethylene and water to form ethanol.
00:05
Okay, so first of all we have to write the reaction formula.
00:09
So a part we have ch2 double bond ch2 and we have water.
00:24
This react in presence of acid, acid like h2 -s -o -4.
00:33
Okay and this h2 s4 we use it is actually dilute h2 s4 okay or dilute sulfuric acid and hence we have ethanol ch3 ch2 ohh okay now b part so why do we use this dilute estuctorsophor or acid so acid like dilute testisophore acts like a catalyst as it protonates and makes carboketion intermediate which is reactive to readily react with water.
02:11
Write it again to form ethanol.
02:24
Now see part what do we call this type of reaction? so this reaction let me write it again this reaction is called acid catalyzed hydration.
03:00
Okay now finally we have to write the mechanism for such reaction.
03:14
So this is ch2 double bond ch2 okay.
03:19
Now first of all this estuosovo being an acid being a good strong acid it releases h positive ion.
03:29
Okay, this h positive ion leads to protonation.
03:34
So first step is protonation that is adding of proton okay so these double bonded carbon atoms they act as electron -rich center and one of the carbon atom approaches the electron deficient hydrogen ion and hence we have carbogation here okay so ch2 positive charge single bond ch3 so hydrogen atom has added to this carbon okay so this is the carbon we have okay so carboketion has been formed now this is of course the one degree carbogation.
04:33
Now what will happen that now water being a good nucleophile, okay, acting as a good nucleophile.
04:42
So that water will approach...