12.) ? Ii 12V β = 120 ro =...

12.) ? $I_i$ 12V $\beta = 120$ $r_o = 40k\Omega$ $Z_i$ $390k\Omega$ $5.6k\Omega$ $-8V$ $Z_o$ 13.) $V_{CC} = 20V$ $56k\Omega$ $V_i$ $\beta = 200$ $r_o = 40k\Omega$ $I_i$ $6.2k\Omega$ $2k\Omega$ $V_o$ Given: $\beta = 200$ $r_o = 40k\Omega$ 14.) 20V $5pF$ $2.2k\Omega$ $470\Omega$ $5pF$ $V_i$ $Z_i$ $1k\Omega$ $10pF$ $V_o$ $Z_o$ Given $r_{ie} = 275k\Omega$ $h_{fe} = 180$ $h_{oe} = 20\mu S$ $h_{re} = 2 \times 10^{-4}$

Transcript

00:01 Hello students, let us look on this question.

00:02 So, in this question we have given this circuit and we have to find the voltage and current across all the registers.

00:07 First of all what we have given here we have given the battery of 10 voltage, then we have given the values of r1, r2, r3 and r4 respectively are this is 10 ohm sorry this is the 15 ohm, this is the 10 ohm, this is 33 ohm and this is the 55 ohm, okay.

00:28 Moving on the procedure, so first of all what i have requirement i have to find the r equivalent.

00:33 So, these two registers are in parallel, then after equivalent of this will be the series with this r1 and r2.

00:40 So, first of all i am finding the r dash equivalent of this two that will be equal to r3, r4 upon r3 plus r4.

00:49 So, put the values here, what is the value of r3 and what is the value of r3 here 33 multiply with 55 divide by 33 plus 55.

00:59 So, i will have the r dash is equal to after solving this value 26 .565 ohm and what is the value of now r equivalent.

01:08 So, r equivalent is equal to simply 21 .65 plus 15 plus 10.

01:14 So, i will have total value 45 .6 ohm.

01:17 Moving on the current value, so i is equal to v by r net current flowing in the circuit i is equal to v by r equivalent.

01:24 So, v is equal to 10 r equivalent is equal to 45 .6.

01:27 So, i will total answer have i is equal to 0 .21.

01:32 So, from this simple observation we can see current i is flowing from r1 and from r2 because it is in series combination and i current is distributed between these two values r4 r3 and r4...

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