00:02
The way i would attack this problem is start by rewriting this function, negative 3, sine of 2x minus pi over 2.
00:12
I know some different teachers might have some different strategies, but what i would do, i'm fine with this negative 3, but what i would do is factor out the 2 out of that x.
00:22
And what you have to do then is be smart about what value goes here.
00:27
Now, the pie so i say go there, but as i distribute two times what would give me pi or two, and i hope it makes sense it would be pi over four, because doubling pi over four would get me to pi or two.
00:39
So then what i can do is i can answer a few of these questions, that the amplitude is three.
00:46
That negative that's in front makes it a reflection.
00:52
So i'll talk about that here in a second.
00:55
This 2 is telling me that the period, that 2 is not part of the period.
01:02
Because the normal period would be 2 pi.
01:04
You divide by that number.
01:06
So the period in this problem would just be pi.
01:08
And then the phase shift is shifted right because it's a minus pi over 4.
01:18
There is no vertical shift...