Question

12) In an experiment, (120 + Y) mL 0.6 M Na2SO4 solution is mixed with 300 mL 0.45 M BaCiz solution and BaSO4 precipitate (solid) is formed according to the below reaction. Calculate the amount of precipitate in grams.. (Atomic mass: Na = 23, 0 = 16, S = 32, Ba = 137, CI= 35) NazSO4(aq) + BaC2(aq) -> 2NaCI(aq) + BaSO4(S)

Name: 12 in an experiment 120 y ml 06 m na2so4 solution is mixed with 300 ml 045 m baciz solution and baso4 precipitate solid is formed according to the below reaction calculate the amount of precipitate in
Uploaded: 2023-03-19T23:36:51-08:00
Duration: 3 min 11 s
Channel: Supreeta N
Description: 12 in an experiment 120 y ml 06 m na2so4 solution is mixed with 300 ml 045 m baciz solution and baso4 precipitate solid is formed according to the below reaction calculate the amount of precipitate in

          12) In an experiment, (120 + Y) mL 0.6 M Na2SO4 solution is mixed with 300 mL 0.45 M BaCiz solution and BaSO4 precipitate (solid) is formed according to the below reaction. Calculate the
amount of precipitate in grams.. (Atomic mass: Na = 23, 0 = 16, S = 32, Ba = 137, CI= 35)
NazSO4(aq) + BaC2(aq) -> 2NaCI(aq) + BaSO4(S)

Added by Lion G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Supreeta N

03/19/2023

Step 1

6 mol/L x (120 + Y) mL = 0.6 mol/L x 0.12 L = 0.072 mol Show more…

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12) In an experiment, (120 + Y) mL 0.6 M Na2SO4 solution is mixed with 300 mL 0.45 M BaCiz solution and BaSO4 precipitate (solid) is formed according to the below reaction. Calculate the amount of precipitate in grams.. (Atomic mass: Na = 23, 0 = 16, S = 32, Ba = 137, CI= 35) NazSO4(aq) + BaC2(aq) -> 2NaCI(aq) + BaSO4(S)