12. In the presence of CN?, Fe³? forms the complex ion Fe(CN)?³?. The equilibrium concentrations of Fe³? and Fe(CN)?³? are 8.5 x 10??? M and 1.5 x 10?³ M, respectively, in a 0.11 M KCN solution. Calculate the value of the overall formation constant of Fe(CN)?³?. Fe³?(aq) + 6CN?(aq) ? Fe(CN)?³?(aq) Kf=
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The reaction is: \[ \mathrm{Fe}^{3+}(aq) + 6\mathrm{CN}^{-}(aq) \rightleftharpoons \mathrm{Fe}(\mathrm{CN})_{6}^{3-}(aq) \] We are asked to find the overall formation constant (\(K_f\)) for this reaction. Show more…
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In the presence of $\mathrm{CN}^{-}, \mathrm{Fe}^{3+}$ forms the complex ion $\mathrm{Fe}(\mathrm{CN})_{6}^{3-} .$ The equilibrium concentrations of $\mathrm{Fe}^{3+}$ and $\mathrm{Fe}(\mathrm{CN})_{6}^{3-}$ are $8.5 \times 10^{-40} \mathrm{M}$ and $1.5 \times 10^{-3} M,$ respectively, in a $0.11-M$ KCN solution. Calculate the value for the overall formation constant of $\mathrm{Fe}(\mathrm{CN})_{6}^{3-}$ . $$\mathrm{Fe}^{3+}(a q)+6 \mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{Fe}(\mathrm{CN})_{6}^{3-}(a q) \qquad K_{\text { overall }}=?$$
In the presence of $\mathrm{CN}^{-}, \mathrm{Fe}^{3+}$ forms the complex ion $\mathrm{Fe}(\mathrm{CN})_{6}^{3-}$. The equilibrium concentrations of $\mathrm{Fe}^{3+}$ and $\mathrm{Fe}(\mathrm{CN})_{6}^{3-}$ are $8.5 \times 10^{-40} M$ and $1.5 \times 10^{-3} M$, respectively, in a $0.11-M$ KCN solution. Calculate the value for the overall formation constant of $\mathrm{Fe}(\mathrm{CN})_{6}{ }^{3-}$. $\mathrm{Fe}^{3+}(a q)+6 \mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{Fe}(\mathrm{CN})_{6}^{3-}(a q) \quad K_{\text {ovemull }}=?$
In the presence of $\mathrm{CN}^{-}, \mathrm{Fe}^{3+}$ forms the complex ion $\mathrm{Fe}(\mathrm{CN})_{6}^{3-}$ The equilibrium concentrations of $\mathrm{Fe}^{3+}$ and $\mathrm{Fe}(\mathrm{CN})_{6}^{3-}$ are $8.5 \times 10^{-40} M$ and $1.5 \times 10^{-3} M,$ respectively, in a $0.11-M$ KCN solution. Calculate the value for the overall formation constant of $\mathrm{Fe}(\mathrm{CN})_{6}^{3-}$ $$\mathrm{Fe}^{3+}(a q)+6 \mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{Fe}(\mathrm{CN})_{6}^{3-}(a q) \quad K_{\mathrm{overall}}=?$$
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