00:01
Hello students, for question number 2, it is given that the voltage of the battery v is 15v and voltage drop across the led in forward bias, voltage drop across led in forward bias, that is small v equal to 2v and the resistance of the series resistor are equal to 2 .2k.
00:35
So in this given problem, led is in forward bias with battery and is connected with a resistor in series.
00:44
So first let's draw the circuit diagram.
00:52
So let it be the battery which is 15v and is forward biased with a led.
01:11
So this is the led and it is in series connection with a resistor.
01:30
So the resistor are equal to 2 .2k and the circuit is closed.
01:39
So this is the circuit for the initial case.
01:45
So now let's solve the problem.
01:48
In forward biased condition, the diode conducts the electric current only when applied voltage is greater than the threshold value.
02:05
So after that the voltage drop across the diode is constant.
02:10
The net potential difference, the net potential difference across the battery and the diode is, that is v equivalent is equal to v minus small v.
02:37
Here v is 15v and the small v is 2v.
02:42
So therefore the equivalent voltage is 13v.
02:48
Now for this voltage and the resistor of 2 .2k ohm, we are going to current the equivalent current.
02:57
So first we have to draw the equivalent circuit...