Question

onsider the points A, B and C Student 4: A(-3,3) B(3,1) C(-1,-3) 1. Calculate the distances between the points and classify the triangle ABC 2. Find the midpoint M of the line segment [BC] 3. Use gradients to show that [AM] and [BC] are perpendicular 4. What would be the gradient of a line perpendicular to [AC] 5. Determine which line segment ([AB], [BC] or [AC]) belongs to the following equat Student 4 y=\frac{1}{3}x+2

          onsider the points A, B and C
Student 4: A(-3,3) B(3,1) C(-1,-3)
1. Calculate the distances between the points and classify the triangle ABC
2. Find the midpoint M of the line segment [BC]
3. Use gradients to show that [AM] and [BC] are perpendicular
4. What would be the gradient of a line perpendicular to [AC]
5. Determine which line segment ([AB], [BC] or [AC]) belongs to the following equat
Student 4
y=\frac{1}{3}x+2

onsider the points A, B and C
Student 4: A(-3,3) B(3,1) C(-1,-3)
1. Calculate the distances between the points and classify the triangle ABC
2. Find the midpoint M of the line segment [BC]
3. Use gradients to show that [AM] and [BC] are perpendicular
4. What would be the gradient of a line perpendicular to [AC]
5. Determine which line segment ([AB], [BC] or [AC]) belongs to the following equat
Student 4
y=(1)/(3)x+2

Added by Kendra D.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Kajal Gautam

Step 1

Calculate the distances between the points A, B, and C: - The distance between A(-3,3) and B(3,?) can be found using the distance formula: dAB = √((x2 - x1)^2 + (y2 - y1)^2) = √((3 - (-3))^2 + (? - 3)^2) = √(6^2 + (? - 3)^2) = √(36 + (? - 3)^2) - The Show more…

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Consider the points A, B and C: A(-3,3), B(3,?), C(-1,3). Calculate the distances between the points and classify the triangle ABC. Find the midpoint M of the line segment [BC]. Use gradients to show that [AM] and [BC] are perpendicular. What would be the gradient of a line perpendicular to [AC]? Determine which line segment (AB), (BC), or (AC) belongs to the following equation: y = mx + 2.