Question

Which of the following equations is/are correct? [2 marks] 1234$_8$ = 29C$_{16}$ (i) 1101 1010 0101$_2$ = AC5$_{16}$ 3216$_{10}$ = 6220$_8$ 270$_8$ = 1001 1011 (ii) (iii) (iv) (i) and (iii) (i) and (ii) (ii) and (iv) All of the above

          Which of the following equations is/are correct? [2 marks]
1234$_8$ = 29C$_{16}$
(i)
1101 1010 0101$_2$ = AC5$_{16}$  3216$_{10}$ = 6220$_8$  270$_8$ = 1001 1011
(ii)
(iii)
(iv)
(i) and (iii)
(i) and (ii)
(ii) and (iv)
All of the above

Which of the following equations is/are correct? [2 marks]
12348 = 29C16
(i)
1101 1010 01012 = AC516 321610 = 62208 2708 = 1001 1011
(ii)
(iii)
(iv)
(i) and (iii)
(i) and (ii)
(ii) and (iv)
All of the above

Added by Carlos W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kajal Raghubanshi

Step 1

Convert 1234_8 to binary by octal digits: 1→001, 2→010, 3→011, 4→100, so binary = 001 010 011 100 = 001010011100. Group into 4-bit nibbles: 0010 1001 1100 = 2 9 C, so 1234_8 = 29C_16. (i) is correct. Show more…

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