00:01
To determine the boiling point and freezing point of the solution, we need to first calculate the molality of glycerol.
00:09
The molality of glycerol will be the moles of glycerol, which can be calculated by taking the mass of glycerol.
00:18
0 .133 grams and dividing it by its molar mass, 1 mole glycerol has a mass of 92 .0 .0 .3 grams.
00:31
So 9 4 grams.
00:35
We then divide that by the kilograms of just water.
00:43
It was added to 20 grams of water, which corresponds to 0 .020 kilograms of water.
00:56
So we have a molality of 7 .22 times 10 to the negative 2 moles per kilogram.
01:07
And then the freezing point can be determined from the change in freezing point, which will be equal to the molality, 7 .22, times 10 to the negative 2, multiplied by kf for water, which is negative 1 .86 degrees celsius per molal...