128; 64;....form a geometric sequence, de If $ax^2 + 2bx + c = 0$ has equal roots, prove that $a$; $b$; $c$ forms a geometric sequence Given the series:

          128; 64;....form a geometric sequence, de
If $ax^2 + 2bx + c = 0$ has equal roots, prove that $a$; $b$; $c$ forms a geometric sequence
Given the series:

Added by James R.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Daniel Pyda

Step 1

This means that the ratio between consecutive terms is constant. Let's call this ratio "r". So, we have: 64 = 128/r Show more…

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128 and 64 form a geometric sequence; deteffft If ar^2 + 2br + c = 0 has equal roots, prove that a, b, c forms a geometric sequence Given the series:

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128; 64;....form a geometric sequence, de If $ax^2 + 2bx + c = 0$ has equal roots, prove that $a$; $b$; $c$ forms a geometric sequence Given the series:

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