00:01
Hello everyone we are going to understand this question.
00:05
So from the given diagram from the given diagram let's draw the fvd.
00:21
The weight of the block is vertically downward that is m into g and tension in the string is t which is in upward direction so here tension in vertical string that is represented by tv so t v is in upward direction and m g is in downward direction net acceleration is in downward direction and tension in the string that is t h and net acceleration in the left side and weight of the block that is 3m plus 2m into g and normal reaction is in upward direction and weight of the 3m block is in downward and normal reaction is in upward direction.
01:22
Due to motion of this block, there will be a friction force, which is in left side, which is in right side due to which this block will move with certain acceleration and there will be a pseudo force that is equal to 3m into a.
01:42
So we can write m into z minus t v is equal to m into a let this is equation one and for horizontal force so we can write t h is equal to 3m plus 2m into a or we can write t h is equal to 5m into a so we can write t v minus t h is equal to i into alpha or we can write sorry t v minus t h into r is equal to i into alpha or we can write tv minus t h is equal to moment of inertia of disk that is 2 m r square into alpha upon r here r and r will get cancelled so we will get t v minus t h is equal to 2m .a.
03:05
Let this is equation 3.
03:07
Now from equation 1, 2 and 3, from equation 1, 2 and 3, we can write m g is equal to ma plus 5m a plus 2m.
03:41
Now after doing further calculation we will get a is equal to g upon 8...