00:01
Hello students, let's discuss the question.
00:03
So here we have 1 -3 -butadine which undergo electrophilic addition with hbr.
00:09
So this is 1 -3 -butadine and this is hbr that is hydrogen bromide.
00:21
So here we need to complete the steps in the mechanism to produce the product as shown.
00:27
So here when this 1 -3 -butadine reacts with hb -r, so what happens this double bond is converted this double ones directly act on this hydrogen atoms and because of these the bond which forms will be something like this here we'll be having you will be having hydrogen and here it will be ch3 the double bond will double bond attacked on this hydrogen and this hydrogen will link over here and here will be having carbocatal here will be having hydrogen and here we'll be having a double bond.
01:05
This is the methyl group.
01:07
So now what happens? the br, this br has three lone pair of electrons.
01:11
So what happens is br directly attacked on this hydrogen.
01:15
Okay, so this br will attack on this hydrogen.
01:18
Let's draw it over here...