Question

13) For each rational function, determine the domain, holes, x-intercepts, y-intercepts, and asymptotes. If there isn't one, just write none. Then, graph the function. f(x) = (x^2 + 3x - 4) / (x^2 + 4x) Domain: Holes: x-intercepts: y-intercept: Vertical Asymptote(s): Horizontal Asymptote: Oblique Asymptote: Skip -> f(x) = (x^2 + 5x + 6) / (-2x^2 + 4x + 6) Domain: Holes: x-intercepts: y-intercept: Vertical Asymptote(s): Horizontal Asymptote:

          13) For each rational function, determine the domain, holes, x-intercepts, y-intercepts, and asymptotes. If there isn't one, just write none. Then, graph the function.
f(x) = (x^2 + 3x - 4) / (x^2 + 4x)
Domain: 
Holes: 
x-intercepts: 
y-intercept: 
Vertical Asymptote(s): 
Horizontal Asymptote: 
Oblique Asymptote: 

Skip -> f(x) = (x^2 + 5x + 6) / (-2x^2 + 4x + 6)
Domain: 
Holes: 
x-intercepts: 
y-intercept: 
Vertical Asymptote(s): 
Horizontal Asymptote:

13) For each rational function, determine the domain, holes, x-intercepts, y-intercepts, and asymptotes. If there isn't one, just write none. Then, graph the function.
f(x) = (x^2 + 3x - 4) / (x^2 + 4x)
Domain:
Holes:
x-intercepts:
y-intercept:
Vertical Asymptote(s):
Horizontal Asymptote:
Oblique Asymptote:

Skip -> f(x) = (x^2 + 5x + 6) / (-2x^2 + 4x + 6)
Domain:
Holes:
x-intercepts:
y-intercept:
Vertical Asymptote(s):
Horizontal Asymptote:

Added by Destiny B.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Kathleen Carty

04/16/2022

Step 1

In this case, since there is no denominator, the domain is all real numbers. Show more…

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13) For each rational function, determine the domain, holes, x-intercepts, y-intercepts, and asymptotes. If there isn't one, just write none. Then, graph the function. f(x) = (x^2 + 3x - 4) / (x^2 + 4x) Domain: Holes: x-intercepts: y-intercept: Vertical Asymptote(s): Horizontal Asymptote: Oblique Asymptote: f(x) = (x^2 + 5x + 6) / (-2x^2 + 4x + 6) Domain: Holes: x-intercepts: y-intercept: Vertical Asymptote(s): Horizontal Asymptote: