00:01
Enthalpy change for 1 mole of methane, enthalpy change delta h is minus 891 kilojoules.
00:15
If there will be the combustion reaction, that is, ch4 plus 2o2 will give carbon dioxide co2 plus 2h2 plus 2h2.
00:29
So, here we are going to see for 1 .5 kilogram of methane, what will be the change in n -30.
00:37
As we see, 1 mole means the molecular mass of methane, which is 16 gram.
00:48
For 16 gram, delta h is minus 891 kilojoules.
00:54
So it is asked to find out 1 .5 kilogram which is 15.
01:00
1500 grams.
01:02
So, 1 ,500 grams of methane, the enthalpy change will be minus 891 divided by 15 multiplied with 1500.
01:19
And the value is 83 ,531 .255.
01:29
So here the change in enthalpy is, is 83 ,531 .252g.
01:41
This is the value of change in enthalpy delta h.
01:48
Next, we will see the reaction 3 c2h2 gives c6h6.
01:57
The value of entropy for c2h2 is 200 .8 jules per mole kelvin and entropy for c6 is 172 .8 joules per mole kelvin.
02:20
Here we are going to find out change in entropy, delta s will be s chero product minus of s standard entropy of the reality.
02:34
Here we have the values of the product and reactant.
02:39
Product is h6 minus h0 reactant is c2 h2.
02:47
So the value, if it will put it will be 172.
02:56
As there is presence of 3 moles of 6 to c2 h2...