CDF of X: P(X ≤ x) = 1 - P(X > x) = 1 - P(min(U, V) > x) = 1 - P(U > x, V > x)
Since U and V are independent, we have:
P(U > x, V > x) = P(U > x) * P(V > x) = (1 - x) * (1 - x) = (1 - x)^2
So, the CDF of X is:
P(X ≤ x) = 1 - (1 - x)^2
Now, we can find the
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