00:01
Hi, for the a part of the equation, concentration of atoms per unit volume in nm raised to –3 can be found from the formula n is equal to 8 by a cube into 1 by 10 raised to 3 the whole cube.
00:19
Now, substitute the value of a as 0 .543 nm, we get the answer as n is equal to 50 atoms per nanometer cube.
00:35
Moving to the b part of the equation, for 1 0 0 plane structure, number of atoms per unit cell is n is equal to 4 into 1 by 4 plus 1 which is equal to 2.
00:53
Therefore, number of atoms is 1 0 0 is equal to 2 by 0 .543 into 1 by 10 raised to 3 the whole square which is equal to 6 .78 into 10 raised to 18 atoms per meter cube.
01:19
In the same manner, for plane structure 1 1 0, the number of atoms per unit cell n will be equal to 4 into 1 by 4 plus 2 into 1 by 2 plus 2 which is equal to 4.
01:35
So, n 1 1 0 will be equal to 4 by square root of 2 into 0 .543 into 10 raised to minus 3 the whole square into 1 by 10 raised to 9 the whole square.
01:56
On solving, we will get n 1 1 0 is equal to 9 .59 into 10 raised to 18 atoms per meter square.
02:11
Now, similarly for 1 1 1 plane structure, number of atoms per unit cell n is equal to 3 into 60 by 360 plus 3 into 1 by 2 will be equal to 2.
02:28
So, n 1 1 1 is equal to number of atoms per unit cell by 2 into 1 by 2 into a root 2 divided by 2 into a root 3 divided by 2 multiplied by 1 by 10 raised to 9 the whole square...