00:01
Hello everyone, we are going to understand this question.
00:05
We are given in the question, given mass of the block, mass of the box, mass of box that is represented by m which is 2 kg and coefficient of static friction, coefficient of static friction that is represented by mu which is 0 .4.
00:47
Here a force is applied on the box that is at angle 30 degree with the inclined plane.
00:58
Now taking the component of weight.
01:01
So first of all we can see that component of weight that is working vertically downward, that is mg.
01:10
Now taking the component perpendicular to the plane.
01:14
Let's represent this on the, that this is the inclined plane, weight of the object mg, that is in downward.
01:24
Now taking the component of weight with respect to the plane.
01:28
So perpendicular component with respect to plane that is mg cost theta and along to incline plane that is mg sine theta.
01:39
And this will be balanced by the normal reaction.
01:47
And here of force is applied on the box at angle 30 degree with inclined plane...